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Speed made good over the watch: the ground, not the log

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Distance–time graph of one watch: speed made good is the slope from fix to fix over the whole watchDistance–time graph of a 4 h watch, both axes to scale. The ship made good 53.6 nm between the two plotted positions, so the speed made good is 53.6 ÷ 4 = 13.4 kn, the slope of the line from fix to fix over the whole watch. The log showed 56.2 nm over the same watch (14.05 kn through the water); the 2.6 nm between the two is log − ground: the current along her track (and any log error). The 0.5 h the engines were stopped stays inside the 4 h.DISTANCE–TIME · ONE WATCHdistance (nm)time (h)01234end of watchlog 56.2 nmfix 53.6 nm2.6 nmlog − groundlog: 56.2 ÷ 4 = 14.05 knthrough the waterspeed made good53.6 ÷ 4 = 13.4 knfixengines stopped 0.5 hstays in the 4 h; time drawn as an example

The rule

  • Measure the distance on the chart between the fix at the start and the fix at the end of the watch: that is where she actually got to.
  • Divide it by the whole length of the watch. A stoppage stays in, because the next watch will have its own delays.
  • The log measures water past the hull, not ground covered; keep its distance for the comparison, not for the speed.
  • Log distance − ground distance shows the current along her track (and any log error): note it every watch.

Formula

  • Speed made good = distance between the plotted positions ÷ whole length of the watch
  • Current along the track (and any log error) = log distance − distance made good

Worked example

Distance made good between the two plotted positions53.6 nm
Distance shown by the log over the same watch56.2 nm
Length of the watch4 h
Time the engines were stopped during the watch0.5 h
  1. Ground covered = distance between the plotted positions = 53.6 nm (not the log's 56.2 nm)
  2. Time = the whole watch, stoppage included = 4 h
  3. For the record: log − ground = 56.2 − 53.6 = 2.6 nm, the current (and any log error)
  4. Speed made good = 53.6 ÷ 4 = 13.4 kn

Answer13.4 kn

Common mistake

Dividing by 3.5 h, the hours she was moving, instead of the 4 h watch.

15.31 kn is what she did between stops; an ETA built on it assumes the rest of the passage will have no stops at all, and she arrives late.