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Stability & CargoPage 10 of 12

Displacement in dock water: correct the table figure for density

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Displacement in dock water: one immersed volume, weighed at the tables' density and at the density alongsideMidship section at the survey draft. The draft fixes the immersed volume: 158420 ÷ 1.025 = 154556 m³, the same in any water. Weighed at the tables' density, 1.025 t/m³, it is the table displacement, 158420 t; weighed at the density sampled alongside, 1.0135 t/m³, it is the corrected displacement: 158420 × 1.0135 ÷ 1.025 = 156643 t.immersed volume154556 m³fixed by the draft · the same in any watertables1.025 t/m³alongside1.0135 t/m³DISPLACEMENT, T (SCALE MAGNIFIED)× 1.025 = 158420 t× 1.0135 = 156643 t1560001570001580001590001777 t lighterSection · one waterline · displacement axis starts above zero

The rule

  • Entered with the survey mean draft, the hydrostatic table gives a displacement worked for the density its tables are computed for — 1.025 t/m³ unless the booklet says otherwise.
  • What the draft really fixes is the immersed volume: table displacement ÷ table density. That volume does not change with the water she floats in.
  • Sample the water alongside, read its density, and weigh the same volume of that water: corrected displacement = table displacement × observed density ÷ table density.
  • Check the direction every time: water lighter than the tables' must give the smaller figure.

Formula

  • Immersed volume = table displacement ÷ table density
  • Corrected displacement = table displacement × observed density ÷ table density

Worked example

Displacement read from the tables158420 t
Density the hydrostatic tables are computed for1.025 t/m³
Density of the water sampled alongside1.0135 t/m³
  1. Immersed volume = 158420 ÷ 1.025 = 154556 m³
  2. Corrected displacement = 158420 × 1.0135 ÷ 1.025 = 156643 t

Answer156643 t

Common mistake

Turning the ratio upside down: 158420 × 1.025 ÷ 1.0135 = 160218 t.

The volume has not changed, only the weight of the water it holds, and water of 1.0135 t/m³ is lighter than the tables' 1.025: a correction that makes her heavier has gone the wrong way, and in a draft survey it turns into 3575 t of cargo that is not on board.